Base | Representation |
---|---|
bin | 111110000111101100… |
… | …1000000110101100001 |
3 | 110202100000202222121121 |
4 | 1330033121000311201 |
5 | 4141201430421231 |
6 | 141141212052241 |
7 | 12431555000665 |
oct | 1741731006541 |
9 | 422300688547 |
10 | 133402201441 |
11 | 51637079463 |
12 | 21a30164081 |
13 | c76c9bb692 |
14 | 665728a8a5 |
15 | 370b8a3311 |
hex | 1f0f640d61 |
133402201441 has 8 divisors (see below), whose sum is σ = 135235988640. Its totient is φ = 131568586272.
The previous prime is 133402201433. The next prime is 133402201459. The reversal of 133402201441 is 144102204331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 133402201441 - 23 = 133402201433 is a prime.
It is a super-2 number, since 2×1334022014412 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133402211441) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2794350 + ... + 2841688.
It is an arithmetic number, because the mean of its divisors is an integer number (16904498580).
Almost surely, 2133402201441 is an apocalyptic number.
It is an amenable number.
133402201441 is a deficient number, since it is larger than the sum of its proper divisors (1833787199).
133402201441 is an equidigital number, since it uses as much as digits as its factorization.
133402201441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 86015.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 133402201441 its reverse (144102204331), we get a palindrome (277504405772).
The spelling of 133402201441 in words is "one hundred thirty-three billion, four hundred two million, two hundred one thousand, four hundred forty-one".
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