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133402344451 = 533511716897
BaseRepresentation
bin111110000111101100…
…1100011110000000011
3110202100001001020210021
41330033121203300003
54141202000010301
6141141215114311
712431556134635
oct1741731436003
9422301036707
10133402344451
1151637166952
1221a30212997
13c76ca3b7bc
1466572c6a55
15370b8d08a1
hex1f0f663c03

133402344451 has 8 divisors (see below), whose sum is σ = 135958271904. Its totient is φ = 130847857920.

The previous prime is 133402344353. The next prime is 133402344463. The reversal of 133402344451 is 154443204331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 133402344451 - 233 = 124812409859 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133402347451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 172366 + ... + 544531.

It is an arithmetic number, because the mean of its divisors is an integer number (16994783988).

Almost surely, 2133402344451 is an apocalyptic number.

133402344451 is a deficient number, since it is larger than the sum of its proper divisors (2555927453).

133402344451 is an equidigital number, since it uses as much as digits as its factorization.

133402344451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 720461.

The product of its (nonzero) digits is 69120, while the sum is 34.

Adding to 133402344451 its reverse (154443204331), we get a palindrome (287845548782).

The spelling of 133402344451 in words is "one hundred thirty-three billion, four hundred two million, three hundred forty-four thousand, four hundred fifty-one".

Divisors: 1 53 3511 186083 716897 37995541 2517025367 133402344451