133404021110131 has 2 divisors, whose sum is σ = 133404021110132. Its totient is φ = 133404021110130.

The previous prime is 133404021110119. The next prime is 133404021110147. The reversal of 133404021110131 is 131011120404331.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133404021110131 is a prime.

It is a super-2 number, since 2×133404021110131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133404021110096 and 133404021110105.

It is not a weakly prime, because it can be changed into another prime (133404021111131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66702010555065 + 66702010555066.

It is an arithmetic number, because the mean of its divisors is an integer number (66702010555066).

Almost surely, 2^{133404021110131} is an apocalyptic number.

133404021110131 is a deficient number, since it is larger than the sum of its proper divisors (1).

133404021110131 is an equidigital number, since it uses as much as digits as its factorization.

133404021110131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 133404021110131 its reverse (131011120404331), we get a palindrome (264415141514462).

The spelling of 133404021110131 in words is "one hundred thirty-three trillion, four hundred four billion, twenty-one million, one hundred ten thousand, one hundred thirty-one".