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13340405051 = 22039605309
BaseRepresentation
bin11000110110010011…
…00110110100111011
31021102201022210101222
430123021212310323
5204310120430201
610043431102255
7651405400121
oct143311466473
937381283358
1013340405051
115726346846
12270381198b
131347a787cc
14907a59911
1553129291b
hex31b266d3b

13340405051 has 4 divisors (see below), whose sum is σ = 13341032400. Its totient is φ = 13339777704.

The previous prime is 13340405027. The next prime is 13340405063. The reversal of 13340405051 is 15050404331.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15050404331 = 112913330739.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13340405051 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13340405051.

It is not an unprimeable number, because it can be changed into a prime (13340405851) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 280616 + ... + 324693.

It is an arithmetic number, because the mean of its divisors is an integer number (3335258100).

Almost surely, 213340405051 is an apocalyptic number.

13340405051 is a deficient number, since it is larger than the sum of its proper divisors (627349).

13340405051 is an equidigital number, since it uses as much as digits as its factorization.

13340405051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 627348.

The product of its (nonzero) digits is 3600, while the sum is 26.

Adding to 13340405051 its reverse (15050404331), we get a palindrome (28390809382).

The spelling of 13340405051 in words is "thirteen billion, three hundred forty million, four hundred five thousand, fifty-one".

Divisors: 1 22039 605309 13340405051