Base | Representation |
---|---|
bin | 1100001000100000111001… |
… | …0111000010101111111011 |
3 | 1202020022221001201212111212 |
4 | 3002020032113002233323 |
5 | 3222032124242433341 |
6 | 44212255514113335 |
7 | 2544545531311424 |
oct | 302101627025773 |
9 | 52208831655455 |
10 | 13340409342971 |
11 | 42836aa321507 |
12 | 15b556411b84b |
13 | 759cc25cc649 |
14 | 341971c4c64b |
15 | 1820347395eb |
hex | c220e5c2bfb |
13340409342971 has 2 divisors, whose sum is σ = 13340409342972. Its totient is φ = 13340409342970.
The previous prime is 13340409342961. The next prime is 13340409342977. The reversal of 13340409342971 is 17924390404331.
13340409342971 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13340409342971 - 26 = 13340409342907 is a prime.
It is not a weakly prime, because it can be changed into another prime (13340409342977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670204671485 + 6670204671486.
It is an arithmetic number, because the mean of its divisors is an integer number (6670204671486).
Almost surely, 213340409342971 is an apocalyptic number.
13340409342971 is a deficient number, since it is larger than the sum of its proper divisors (1).
13340409342971 is an equidigital number, since it uses as much as digits as its factorization.
13340409342971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1959552, while the sum is 50.
The spelling of 13340409342971 in words is "thirteen trillion, three hundred forty billion, four hundred nine million, three hundred forty-two thousand, nine hundred seventy-one".
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