13341021403441 has 4 divisors (see below), whose sum is σ = 13345186570992. Its totient is φ = 13336856235892.

The previous prime is 13341021403421. The next prime is 13341021403471. The reversal of 13341021403441 is 14430412014331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13341021403441 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13341021403421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2082578971 + ... + 2082585376.

It is an arithmetic number, because the mean of its divisors is an integer number (3336296642748).

Almost surely, 2^{13341021403441} is an apocalyptic number.

It is an amenable number.

13341021403441 is a deficient number, since it is larger than the sum of its proper divisors (4165167551).

13341021403441 is an equidigital number, since it uses as much as digits as its factorization.

13341021403441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4165167550.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 13341021403441 its reverse (14430412014331), we get a palindrome (27771433417772).

The spelling of 13341021403441 in words is "thirteen trillion, three hundred forty-one billion, twenty-one million, four hundred three thousand, four hundred forty-one".