Base | Representation |
---|---|
bin | 1100001000100011010101… |
… | …0101001000101000111001 |
3 | 1202020101121121222220221210 |
4 | 3002020311111020220321 |
5 | 3222034444131413413 |
6 | 44212444431353333 |
7 | 2544600660520623 |
oct | 302106525105071 |
9 | 52211547886853 |
10 | 13341063154233 |
11 | 4283a053935a1 |
12 | 15b5707082849 |
13 | 75a097bb9309 |
14 | 3419d4a01c13 |
15 | 182071d363c3 |
hex | c2235548a39 |
13341063154233 has 16 divisors (see below), whose sum is σ = 18377441275392. Its totient is φ = 8599849440000.
The previous prime is 13341063154121. The next prime is 13341063154241. The reversal of 13341063154233 is 33245136014331.
It is not a de Polignac number, because 13341063154233 - 216 = 13341063088697 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13341063154191 and 13341063154200.
It is not an unprimeable number, because it can be changed into a prime (13341063156233) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 60623568 + ... + 60843233.
It is an arithmetic number, because the mean of its divisors is an integer number (1148590079712).
Almost surely, 213341063154233 is an apocalyptic number.
It is an amenable number.
13341063154233 is a deficient number, since it is larger than the sum of its proper divisors (5036378121159).
13341063154233 is a wasteful number, since it uses less digits than its factorization.
13341063154233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 121468016.
The product of its (nonzero) digits is 233280, while the sum is 39.
Adding to 13341063154233 its reverse (33245136014331), we get a palindrome (46586199168564).
The spelling of 13341063154233 in words is "thirteen trillion, three hundred forty-one billion, sixty-three million, one hundred fifty-four thousand, two hundred thirty-three".
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