Base | Representation |
---|---|
bin | 1100001000100011010101… |
… | …0101001000100111001001 |
3 | 1202020101121121222220210122 |
4 | 3002020311111020213021 |
5 | 3222034444131412441 |
6 | 44212444431353025 |
7 | 2544600660520403 |
oct | 302106525104711 |
9 | 52211547886718 |
10 | 13341063154121 |
11 | 4283a053934aa |
12 | 15b5707082775 |
13 | 75a097bb9251 |
14 | 3419d4a01b73 |
15 | 182071d3634b |
hex | c22355489c9 |
13341063154121 has 2 divisors, whose sum is σ = 13341063154122. Its totient is φ = 13341063154120.
The previous prime is 13341063154087. The next prime is 13341063154241. The reversal of 13341063154121 is 12145136014331.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8544367455625 + 4796695698496 = 2923075^2 + 2190136^2 .
It is a cyclic number.
It is not a de Polignac number, because 13341063154121 - 218 = 13341062891977 is a prime.
It is not a weakly prime, because it can be changed into another prime (13341063154421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670531577060 + 6670531577061.
It is an arithmetic number, because the mean of its divisors is an integer number (6670531577061).
Almost surely, 213341063154121 is an apocalyptic number.
It is an amenable number.
13341063154121 is a deficient number, since it is larger than the sum of its proper divisors (1).
13341063154121 is an equidigital number, since it uses as much as digits as its factorization.
13341063154121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 35.
Adding to 13341063154121 its reverse (12145136014331), we get a palindrome (25486199168452).
The spelling of 13341063154121 in words is "thirteen trillion, three hundred forty-one billion, sixty-three million, one hundred fifty-four thousand, one hundred twenty-one".
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