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13341063154121 is a prime number
BaseRepresentation
bin1100001000100011010101…
…0101001000100111001001
31202020101121121222220210122
43002020311111020213021
53222034444131412441
644212444431353025
72544600660520403
oct302106525104711
952211547886718
1013341063154121
114283a053934aa
1215b5707082775
1375a097bb9251
143419d4a01b73
15182071d3634b
hexc22355489c9

13341063154121 has 2 divisors, whose sum is σ = 13341063154122. Its totient is φ = 13341063154120.

The previous prime is 13341063154087. The next prime is 13341063154241. The reversal of 13341063154121 is 12145136014331.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8544367455625 + 4796695698496 = 2923075^2 + 2190136^2 .

It is a cyclic number.

It is not a de Polignac number, because 13341063154121 - 218 = 13341062891977 is a prime.

It is not a weakly prime, because it can be changed into another prime (13341063154421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670531577060 + 6670531577061.

It is an arithmetic number, because the mean of its divisors is an integer number (6670531577061).

Almost surely, 213341063154121 is an apocalyptic number.

It is an amenable number.

13341063154121 is a deficient number, since it is larger than the sum of its proper divisors (1).

13341063154121 is an equidigital number, since it uses as much as digits as its factorization.

13341063154121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 35.

Adding to 13341063154121 its reverse (12145136014331), we get a palindrome (25486199168452).

The spelling of 13341063154121 in words is "thirteen trillion, three hundred forty-one billion, sixty-three million, one hundred fifty-four thousand, one hundred twenty-one".