Base | Representation |
---|---|
bin | 1100001000100011100001… |
… | …0100011101110011101011 |
3 | 1202020101202010101010100012 |
4 | 3002020320110131303223 |
5 | 3222040100001413233 |
6 | 44212453422402135 |
7 | 2544602140035632 |
oct | 302107024356353 |
9 | 52211663333305 |
10 | 13341113310443 |
11 | 4283a30730706 |
12 | 15b571ba3034b |
13 | 75a0a53ca849 |
14 | 3419db53a519 |
15 | 182076442548 |
hex | c223851dceb |
13341113310443 has 4 divisors (see below), whose sum is σ = 13341217390920. Its totient is φ = 13341009229968.
The previous prime is 13341113310391. The next prime is 13341113310467. The reversal of 13341113310443 is 34401331114331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13341113310443 - 212 = 13341113306347 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13341113310143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51847730 + ... + 52104407.
It is an arithmetic number, because the mean of its divisors is an integer number (3335304347730).
Almost surely, 213341113310443 is an apocalyptic number.
13341113310443 is a deficient number, since it is larger than the sum of its proper divisors (104080477).
13341113310443 is a wasteful number, since it uses less digits than its factorization.
13341113310443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 104080476.
The product of its (nonzero) digits is 15552, while the sum is 32.
Adding to 13341113310443 its reverse (34401331114331), we get a palindrome (47742444424774).
The spelling of 13341113310443 in words is "thirteen trillion, three hundred forty-one billion, one hundred thirteen million, three hundred ten thousand, four hundred forty-three".
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