13341324234201 has 4 divisors (see below), whose sum is σ = 17788432312272. Its totient is φ = 8894216156132.

The previous prime is 13341324234181. The next prime is 13341324234239. The reversal of 13341324234201 is 10243242314331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13341324234201 - 2¹⁵ = 13341324201433 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13341334234201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2223554039031 + ... + 2223554039036.

It is an arithmetic number, because the mean of its divisors is an integer number (4447108078068).

Almost surely, 2^{13341324234201} is an apocalyptic number.

It is an amenable number.

13341324234201 is a deficient number, since it is larger than the sum of its proper divisors (4447108078071).

13341324234201 is an equidigital number, since it uses as much as digits as its factorization.

13341324234201 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4447108078070.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 13341324234201 its reverse (10243242314331), we get a palindrome (23584566548532).

The spelling of 13341324234201 in words is "thirteen trillion, three hundred forty-one billion, three hundred twenty-four million, two hundred thirty-four thousand, two hundred one".