Base | Representation |
---|---|
bin | 10011011010100001010… |
… | …100010101011000100011 |
3 | 11201112122221200102211221 |
4 | 103122201110111120203 |
5 | 133324312424332003 |
6 | 2500522013515511 |
7 | 165250250433403 |
oct | 23324124253043 |
9 | 4645587612757 |
10 | 1334146324003 |
11 | 474898900879 |
12 | 196696aa2b97 |
13 | 98a6a4c389c |
14 | 48804556803 |
15 | 24a86a797bd |
hex | 136a1515623 |
1334146324003 has 4 divisors (see below), whose sum is σ = 1359318896208. Its totient is φ = 1308973751800.
The previous prime is 1334146323997. The next prime is 1334146324037. The reversal of 1334146324003 is 3004236414331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1334146324003 - 221 = 1334144226851 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1334146324003.
It is not an unprimeable number, because it can be changed into a prime (1334146324703) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12586286023 + ... + 12586286128.
It is an arithmetic number, because the mean of its divisors is an integer number (339829724052).
Almost surely, 21334146324003 is an apocalyptic number.
1334146324003 is a deficient number, since it is larger than the sum of its proper divisors (25172572205).
1334146324003 is an equidigital number, since it uses as much as digits as its factorization.
1334146324003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 25172572204.
The product of its (nonzero) digits is 62208, while the sum is 34.
The spelling of 1334146324003 in words is "one trillion, three hundred thirty-four billion, one hundred forty-six million, three hundred twenty-four thousand, three".
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