Base | Representation |
---|---|
bin | 10011011010100100101… |
… | …101011101001010110101 |
3 | 11201112210220210010111002 |
4 | 103122210231131022311 |
5 | 133324422012204031 |
6 | 2500531405453045 |
7 | 165251541300521 |
oct | 23324455351265 |
9 | 4645726703432 |
10 | 1334203241141 |
11 | 474917a46531 |
12 | 1966b1b71185 |
13 | 98a79231574 |
14 | 4880bd30d81 |
15 | 24a8ba6dccb |
hex | 136a4b5d2b5 |
1334203241141 has 16 divisors (see below), whose sum is σ = 1385982005760. Its totient is φ = 1283431706880.
The previous prime is 1334203241089. The next prime is 1334203241143. The reversal of 1334203241141 is 1411423024331.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1334203241141 is a prime.
It is a super-2 number, since 2×13342032411412 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1334203241143) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3605165 + ... + 3957981.
It is an arithmetic number, because the mean of its divisors is an integer number (86623875360).
Almost surely, 21334203241141 is an apocalyptic number.
It is an amenable number.
1334203241141 is a deficient number, since it is larger than the sum of its proper divisors (51778764619).
1334203241141 is a wasteful number, since it uses less digits than its factorization.
1334203241141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 354244.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1334203241141 its reverse (1411423024331), we get a palindrome (2745626265472).
The spelling of 1334203241141 in words is "one trillion, three hundred thirty-four billion, two hundred three million, two hundred forty-one thousand, one hundred forty-one".
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