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1334203241141 = 47611319352817
BaseRepresentation
bin10011011010100100101…
…101011101001010110101
311201112210220210010111002
4103122210231131022311
5133324422012204031
62500531405453045
7165251541300521
oct23324455351265
94645726703432
101334203241141
11474917a46531
121966b1b71185
1398a79231574
144880bd30d81
1524a8ba6dccb
hex136a4b5d2b5

1334203241141 has 16 divisors (see below), whose sum is σ = 1385982005760. Its totient is φ = 1283431706880.

The previous prime is 1334203241089. The next prime is 1334203241143. The reversal of 1334203241141 is 1411423024331.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1334203241141 is a prime.

It is a super-2 number, since 2×13342032411412 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1334203241143) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3605165 + ... + 3957981.

It is an arithmetic number, because the mean of its divisors is an integer number (86623875360).

Almost surely, 21334203241141 is an apocalyptic number.

It is an amenable number.

1334203241141 is a deficient number, since it is larger than the sum of its proper divisors (51778764619).

1334203241141 is a wasteful number, since it uses less digits than its factorization.

1334203241141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 354244.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1334203241141 its reverse (1411423024331), we get a palindrome (2745626265472).

The spelling of 1334203241141 in words is "one trillion, three hundred thirty-four billion, two hundred three million, two hundred forty-one thousand, one hundred forty-one".

Divisors: 1 47 61 1319 2867 61993 80459 352817 3781573 16582399 21521837 465365623 1011526339 21872184281 28387303003 1334203241141