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13342114023404 = 2212914999516839
BaseRepresentation
bin1100001000100111001111…
…1101111000011111101100
31202020111022212101121110012
43002021303331320133230
53222044122142222104
644213141011232352
72544636010666265
oct302116375703754
952214285347405
1013342114023404
1142843a45a1111
1215b595aba86b8
1375a2048273aa
14341a943d196c
151820d4214d6e
hexc2273f787ec

13342114023404 has 24 divisors (see below), whose sum is σ = 23371504800000. Its totient is φ = 6664543315920.

The previous prime is 13342114023401. The next prime is 13342114023409. The reversal of 13342114023404 is 40432041124331.

It is a super-2 number, since 2×133421140234042 (a number of 27 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13342114023401) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25556417 + ... + 26073255.

It is an arithmetic number, because the mean of its divisors is an integer number (973812700000).

Almost surely, 213342114023404 is an apocalyptic number.

It is an amenable number.

13342114023404 is a deficient number, since it is larger than the sum of its proper divisors (10029390776596).

13342114023404 is a wasteful number, since it uses less digits than its factorization.

13342114023404 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 523133 (or 523131 counting only the distinct ones).

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 13342114023404 its reverse (40432041124331), we get a palindrome (53774155147735).

The spelling of 13342114023404 in words is "thirteen trillion, three hundred forty-two billion, one hundred fourteen million, twenty-three thousand, four hundred four".

Divisors: 1 2 4 1291 2582 4999 5164 9998 19996 516839 1033678 2067356 6453709 12907418 25814836 667239149 1334478298 2583678161 2668956596 5167356322 10334712644 3335528505851 6671057011702 13342114023404