Base | Representation |
---|---|
bin | 1100001000100111010100… |
… | …0000010101010100111010 |
3 | 1202020111101002011121122111 |
4 | 3002021311000111110322 |
5 | 3222044141122134002 |
6 | 44213142432442534 |
7 | 2544636312030265 |
oct | 302116500252472 |
9 | 52214332147574 |
10 | 13342131443002 |
11 | 428440340977a |
12 | 15b59649a944a |
13 | 75a20831614b |
14 | 341a96847cdc |
15 | 1820d5a063d7 |
hex | c227501553a |
13342131443002 has 4 divisors (see below), whose sum is σ = 20013197164506. Its totient is φ = 6671065721500.
The previous prime is 13342131442999. The next prime is 13342131443009. The reversal of 13342131443002 is 20034413124331.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 13314405529881 + 27725913121 = 3648891^2 + 166511^2 .
It is not an unprimeable number, because it can be changed into a prime (13342131443009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3335532860749 + ... + 3335532860752.
Almost surely, 213342131443002 is an apocalyptic number.
13342131443002 is a deficient number, since it is larger than the sum of its proper divisors (6671065721504).
13342131443002 is an equidigital number, since it uses as much as digits as its factorization.
13342131443002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6671065721503.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 13342131443002 its reverse (20034413124331), we get a palindrome (33376544567333).
The spelling of 13342131443002 in words is "thirteen trillion, three hundred forty-two billion, one hundred thirty-one million, four hundred forty-three thousand, two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •