Base | Representation |
---|---|
bin | 1100001000100111010110… |
… | …1100100011001010100011 |
3 | 1202020111101212222111112102 |
4 | 3002021311230203022203 |
5 | 3222044202104042034 |
6 | 44213143525121015 |
7 | 2544636512404322 |
oct | 302116554431243 |
9 | 52214355874472 |
10 | 13342143034019 |
11 | 4284409a06228 |
12 | 15b596885916b |
13 | 75a20a843c37 |
14 | 341a981c40b9 |
15 | 1820d6a4597e |
hex | c2275b232a3 |
13342143034019 has 2 divisors, whose sum is σ = 13342143034020. Its totient is φ = 13342143034018.
The previous prime is 13342143033971. The next prime is 13342143034061. The reversal of 13342143034019 is 91043034124331.
It is a strong prime.
It is an emirp because it is prime and its reverse (91043034124331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13342143034019 is a prime.
It is a super-2 number, since 2×133421430340192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13342943034019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6671071517009 + 6671071517010.
It is an arithmetic number, because the mean of its divisors is an integer number (6671071517010).
Almost surely, 213342143034019 is an apocalyptic number.
13342143034019 is a deficient number, since it is larger than the sum of its proper divisors (1).
13342143034019 is an equidigital number, since it uses as much as digits as its factorization.
13342143034019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 38.
The spelling of 13342143034019 in words is "thirteen trillion, three hundred forty-two billion, one hundred forty-three million, thirty-four thousand, nineteen".
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