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13342241130434 = 26671120565217
BaseRepresentation
bin1100001000100111101110…
…0010110000011111000010
31202020111122201120022111222
43002021323202300133002
53222044402212133214
644213201351435042
72544642113250566
oct302117342603702
952214581508458
1013342241130434
11428445a317547
1215b5995685a82
1375a224c6c158
14341aa723b6a6
151820e047138e
hexc227b8b07c2

13342241130434 has 4 divisors (see below), whose sum is σ = 20013361695654. Its totient is φ = 6671120565216.

The previous prime is 13342241130409. The next prime is 13342241130451. The reversal of 13342241130434 is 43403114224331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 13202213245225 + 140027885209 = 3633485^2 + 374203^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13342241130394 and 13342241130403.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3335560282607 + ... + 3335560282610.

Almost surely, 213342241130434 is an apocalyptic number.

13342241130434 is a deficient number, since it is larger than the sum of its proper divisors (6671120565220).

13342241130434 is an equidigital number, since it uses as much as digits as its factorization.

13342241130434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6671120565219.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 13342241130434 its reverse (43403114224331), we get a palindrome (56745355354765).

The spelling of 13342241130434 in words is "thirteen trillion, three hundred forty-two billion, two hundred forty-one million, one hundred thirty thousand, four hundred thirty-four".

Divisors: 1 2 6671120565217 13342241130434