Base | Representation |
---|---|
bin | 111110001000010100… |
… | …0101111010111011011 |
3 | 110202101111002210222021 |
4 | 1330100220233113123 |
5 | 4141222303221103 |
6 | 141143240035311 |
7 | 12432230435554 |
oct | 1742050572733 |
9 | 422344083867 |
10 | 133423101403 |
11 | 51647953959 |
12 | 21a37162b37 |
13 | c774128617 |
14 | 6659d6b32b |
15 | 370d630bbd |
hex | 1f10a2f5db |
133423101403 has 4 divisors (see below), whose sum is σ = 137727072448. Its totient is φ = 129119130360.
The previous prime is 133423101349. The next prime is 133423101431. The reversal of 133423101403 is 304101324331.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304101324331 = 7 ⋅43443046333.
It is a cyclic number.
It is not a de Polignac number, because 133423101403 - 29 = 133423100891 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133423101503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2151985476 + ... + 2151985537.
It is an arithmetic number, because the mean of its divisors is an integer number (34431768112).
Almost surely, 2133423101403 is an apocalyptic number.
133423101403 is a deficient number, since it is larger than the sum of its proper divisors (4303971045).
133423101403 is an equidigital number, since it uses as much as digits as its factorization.
133423101403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4303971044.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 133423101403 its reverse (304101324331), we get a palindrome (437524425734).
The spelling of 133423101403 in words is "one hundred thirty-three billion, four hundred twenty-three million, one hundred one thousand, four hundred three".
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