13343024113 has 4 divisors (see below), whose sum is σ = 14045288560. Its totient is φ = 12640759668.

The previous prime is 13343024099. The next prime is 13343024129. The reversal of 13343024113 is 31142034331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13343024113 - 2³³ = 4753089521 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13343024143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 351132195 + ... + 351132232.

It is an arithmetic number, because the mean of its divisors is an integer number (3511322140).

Almost surely, 2^13343024113 is an apocalyptic number.

It is an amenable number.

13343024113 is a deficient number, since it is larger than the sum of its proper divisors (702264447).

13343024113 is an equidigital number, since it uses as much as digits as its factorization.

13343024113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 702264446.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 13343024113 its reverse (31142034331), we get a palindrome (44485058444).

The spelling of 13343024113 in words is "thirteen billion, three hundred forty-three million, twenty-four thousand, one hundred thirteen".