Base | Representation |
---|---|
bin | 10011011010101010101… |
… | …010111101111001010011 |
3 | 11201120001212222012122212 |
4 | 103122222222331321103 |
5 | 133330123113031201 |
6 | 2500545341222335 |
7 | 165254164336520 |
oct | 23325252757123 |
9 | 4646055865585 |
10 | 1334303252051 |
11 | 474969445180 |
12 | 19671b5619ab |
13 | 98a93b7a013 |
14 | 4881b326147 |
15 | 24a95726abb |
hex | 136aaabde53 |
1334303252051 has 16 divisors (see below), whose sum is σ = 1678808820480. Its totient is φ = 1030178126880.
The previous prime is 1334303252027. The next prime is 1334303252077. The reversal of 1334303252051 is 1502523034331.
It is a de Polignac number, because none of the positive numbers 2k-1334303252051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1334303251999 and 1334303252017.
It is not an unprimeable number, because it can be changed into a prime (1334303252011) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 79480661 + ... + 79497446.
It is an arithmetic number, because the mean of its divisors is an integer number (104925551280).
Almost surely, 21334303252051 is an apocalyptic number.
1334303252051 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1334303252051 is a deficient number, since it is larger than the sum of its proper divisors (344505568429).
1334303252051 is a wasteful number, since it uses less digits than its factorization.
1334303252051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 158978234.
The product of its (nonzero) digits is 32400, while the sum is 32.
Adding to 1334303252051 its reverse (1502523034331), we get a palindrome (2836826286382).
The spelling of 1334303252051 in words is "one trillion, three hundred thirty-four billion, three hundred three million, two hundred fifty-two thousand, fifty-one".
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