Base | Representation |
---|---|
bin | 10011011010101100010… |
… | …101011010001100000011 |
3 | 11201120010211110211120221 |
4 | 103122230111122030003 |
5 | 133330202233431303 |
6 | 2500552215243511 |
7 | 165254653453024 |
oct | 23325425321403 |
9 | 4646124424527 |
10 | 1334331155203 |
11 | 474983173232 |
12 | 196728979597 |
13 | 98a99899767 |
14 | 48820d0ac4b |
15 | 24a97dd94bd |
hex | 136ac55a303 |
1334331155203 has 4 divisors (see below), whose sum is σ = 1404559110760. Its totient is φ = 1264103199648.
The previous prime is 1334331155189. The next prime is 1334331155207. The reversal of 1334331155203 is 3025511334331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1334331155203 - 213 = 1334331147011 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1334331155207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35113977750 + ... + 35113977787.
It is an arithmetic number, because the mean of its divisors is an integer number (351139777690).
Almost surely, 21334331155203 is an apocalyptic number.
1334331155203 is a deficient number, since it is larger than the sum of its proper divisors (70227955557).
1334331155203 is an equidigital number, since it uses as much as digits as its factorization.
1334331155203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70227955556.
The product of its (nonzero) digits is 48600, while the sum is 34.
Adding to 1334331155203 its reverse (3025511334331), we get a palindrome (4359842489534).
The spelling of 1334331155203 in words is "one trillion, three hundred thirty-four billion, three hundred thirty-one million, one hundred fifty-five thousand, two hundred three".
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