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13343341442 = 2241161917099
BaseRepresentation
bin11000110110101001…
…10011101110000010
31021102220211222101012
430123110303232002
5204311343411232
610044014040522
7651442350044
oct143324635602
937386758335
1013343341442
115727a71a12
1227047a9142
131348566212
149081c1a94
155316729b2
hex31b533b82

13343341442 has 16 divisors (see below), whose sum is σ = 20111652000. Its totient is φ = 6639495360.

The previous prime is 13343341441. The next prime is 13343341457. The reversal of 13343341442 is 24414334331.

13343341442 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a super-3 number, since 3×133433414423 (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13343341399 and 13343341408.

It is not an unprimeable number, because it can be changed into a prime (13343341441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 771809 + ... + 788907.

It is an arithmetic number, because the mean of its divisors is an integer number (1256978250).

Almost surely, 213343341442 is an apocalyptic number.

13343341442 is a deficient number, since it is larger than the sum of its proper divisors (6768310558).

13343341442 is a wasteful number, since it uses less digits than its factorization.

13343341442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18961.

The product of its digits is 41472, while the sum is 32.

Adding to 13343341442 its reverse (24414334331), we get a palindrome (37757675773).

The spelling of 13343341442 in words is "thirteen billion, three hundred forty-three million, three hundred forty-one thousand, four hundred forty-two".

Divisors: 1 2 241 482 1619 3238 17099 34198 390179 780358 4120859 8241718 27683281 55366562 6671670721 13343341442