Search a number
-
+
133435143121 = 719062163303
BaseRepresentation
bin111110001000101011…
…0101011001111010001
3110202102022202121002211
41330101112223033101
54141233344034441
6141144350112121
712432435000610
oct1742126531721
9422368677084
10133435143121
1151653728a95
1221a3b1ab641
13c7767835b7
14665b7c3877
15370e70da81
hex1f115ab3d1

133435143121 has 4 divisors (see below), whose sum is σ = 152497306432. Its totient is φ = 114372979812.

The previous prime is 133435143097. The next prime is 133435143137. The reversal of 133435143121 is 121341534331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 133435143121 - 213 = 133435134929 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133435143151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9531081645 + ... + 9531081658.

It is an arithmetic number, because the mean of its divisors is an integer number (38124326608).

Almost surely, 2133435143121 is an apocalyptic number.

It is an amenable number.

133435143121 is a deficient number, since it is larger than the sum of its proper divisors (19062163311).

133435143121 is an equidigital number, since it uses as much as digits as its factorization.

133435143121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19062163310.

The product of its digits is 12960, while the sum is 31.

Adding to 133435143121 its reverse (121341534331), we get a palindrome (254776677452).

The spelling of 133435143121 in words is "one hundred thirty-three billion, four hundred thirty-five million, one hundred forty-three thousand, one hundred twenty-one".

Divisors: 1 7 19062163303 133435143121