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133435242534331 = 433103145175217
BaseRepresentation
bin11110010101101111010000…
…001110110101010110111011
3122111110021200110220011201001
4132111233100032311112323
5114442200334042044311
61151443145411305431
740051243462362223
oct3625572016652673
9574407613804631
10133435242534331
1139575628840a31
1212b707888ab277
13595bb73c7461a
1424d442ba59083
151065e546c34c1
hex795bd03b55bb

133435242534331 has 4 divisors (see below), whose sum is σ = 136538387709592. Its totient is φ = 130332097359072.

The previous prime is 133435242534329. The next prime is 133435242534397.

133435242534331 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133435242534331 - 21 = 133435242534329 is a prime.

It is a super-2 number, since 2×1334352425343312 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133435242534131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1551572587566 + ... + 1551572587651.

It is an arithmetic number, because the mean of its divisors is an integer number (34134596927398).

Almost surely, 2133435242534331 is an apocalyptic number.

133435242534331 is a deficient number, since it is larger than the sum of its proper divisors (3103145175261).

133435242534331 is an equidigital number, since it uses as much as digits as its factorization.

133435242534331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3103145175260.

The product of its digits is 4665600, while the sum is 46.

The spelling of 133435242534331 in words is "one hundred thirty-three trillion, four hundred thirty-five billion, two hundred forty-two million, five hundred thirty-four thousand, three hundred thirty-one".

Divisors: 1 43 3103145175217 133435242534331