13344020120033 has 4 divisors (see below), whose sum is σ = 13352073241860. Its totient is φ = 13335966998208.

The previous prime is 13344020120003. The next prime is 13344020120131. The reversal of 13344020120033 is 33002102044331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7761612125089 + 5582407994944 = 2785967^2 + 2362712^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13344020120033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13344020119984 and 13344020120011.

It is not an unprimeable number, because it can be changed into a prime (13344020120003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4026558428 + ... + 4026561741.

It is an arithmetic number, because the mean of its divisors is an integer number (3338018310465).

Almost surely, 2^{13344020120033} is an apocalyptic number.

It is an amenable number.

13344020120033 is a deficient number, since it is larger than the sum of its proper divisors (8053121827).

13344020120033 is an equidigital number, since it uses as much as digits as its factorization.

13344020120033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8053121826.

The product of its (nonzero) digits is 5184, while the sum is 26.

Adding to 13344020120033 its reverse (33002102044331), we get a palindrome (46346122164364).

The spelling of 13344020120033 in words is "thirteen trillion, three hundred forty-four billion, twenty million, one hundred twenty thousand, thirty-three".