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133440261544307 is a prime number
BaseRepresentation
bin11110010101110011111011…
…011000110101100101110011
3122111110202122021001022001102
4132111303323120311211303
5114442241123423404212
61151445335422155015
740051512035303324
oct3625637330654563
9574422567038042
10133440261544307
1139577773952463
1212b71749722a6b
13595c493a2ab03
1424d478646844b
15106614a1325c2
hex795cfb635973

133440261544307 has 2 divisors, whose sum is σ = 133440261544308. Its totient is φ = 133440261544306.

The previous prime is 133440261544253. The next prime is 133440261544363. The reversal of 133440261544307 is 703445162044331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 133440261544307 - 26 = 133440261544243 is a prime.

It is a super-3 number, since 3×1334402615443073 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (133440261544397) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66720130772153 + 66720130772154.

It is an arithmetic number, because the mean of its divisors is an integer number (66720130772154).

Almost surely, 2133440261544307 is an apocalyptic number.

133440261544307 is a deficient number, since it is larger than the sum of its proper divisors (1).

133440261544307 is an equidigital number, since it uses as much as digits as its factorization.

133440261544307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2903040, while the sum is 47.

The spelling of 133440261544307 in words is "one hundred thirty-three trillion, four hundred forty billion, two hundred sixty-one million, five hundred forty-four thousand, three hundred seven".