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13344110433 = 3212011234537
BaseRepresentation
bin11000110110101111…
…01111011101100001
31021102222022001020100
430123113233131201
5204312043013213
610044042333013
7651452032023
oct143327573541
937388261210
1013344110433
115728447745
122704aba169
131348775244
14908342013
15531775773
hex31b5ef761

13344110433 has 12 divisors (see below), whose sum is σ = 19290890788. Its totient is φ = 8888659200.

The previous prime is 13344110411. The next prime is 13344110447. The reversal of 13344110433 is 33401144331.

It can be written as a sum of positive squares in 2 ways, for example, as 1222761024 + 12121349409 = 34968^2 + 110097^2 .

It is not a de Polignac number, because 13344110433 - 29 = 13344109921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13344110397 and 13344110406.

It is not an unprimeable number, because it can be changed into a prime (13344111433) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 606460 + ... + 628077.

Almost surely, 213344110433 is an apocalyptic number.

It is an amenable number.

13344110433 is a deficient number, since it is larger than the sum of its proper divisors (5946780355).

13344110433 is a wasteful number, since it uses less digits than its factorization.

13344110433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1235744 (or 1235741 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 13344110433 its reverse (33401144331), we get a palindrome (46745254764).

The spelling of 13344110433 in words is "thirteen billion, three hundred forty-four million, one hundred ten thousand, four hundred thirty-three".

Divisors: 1 3 9 1201 3603 10809 1234537 3703611 11110833 1482678937 4448036811 13344110433