Base | Representation |
---|---|
bin | 111110001000110110… |
… | …1011101111001000011 |
3 | 110202102202000010202212 |
4 | 1330101231131321003 |
5 | 4141241411232023 |
6 | 141145122132335 |
7 | 12432536533442 |
oct | 1742155357103 |
9 | 422382003685 |
10 | 133441117763 |
11 | 51657039908 |
12 | 21a411b10ab |
13 | c777a95ba5 |
14 | 665c4dad59 |
15 | 370eedde78 |
hex | 1f11b5de43 |
133441117763 has 2 divisors, whose sum is σ = 133441117764. Its totient is φ = 133441117762.
The previous prime is 133441117757. The next prime is 133441117781. The reversal of 133441117763 is 367711144331.
It is a weak prime.
It is an emirp because it is prime and its reverse (367711144331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133441117763 - 212 = 133441113667 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133441117763.
It is not a weakly prime, because it can be changed into another prime (133441117753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66720558881 + 66720558882.
It is an arithmetic number, because the mean of its divisors is an integer number (66720558882).
Almost surely, 2133441117763 is an apocalyptic number.
133441117763 is a deficient number, since it is larger than the sum of its proper divisors (1).
133441117763 is an equidigital number, since it uses as much as digits as its factorization.
133441117763 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 127008, while the sum is 41.
The spelling of 133441117763 in words is "one hundred thirty-three billion, four hundred forty-one million, one hundred seventeen thousand, seven hundred sixty-three".
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