133444430134051 has 2 divisors, whose sum is σ = 133444430134052. Its totient is φ = 133444430134050.

The previous prime is 133444430134007. The next prime is 133444430134111. The reversal of 133444430134051 is 150431034444331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 133444430134051 - 2¹¹ = 133444430132003 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133444430133995 and 133444430134013.

It is not a weakly prime, because it can be changed into another prime (133444400134051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66722215067025 + 66722215067026.

It is an arithmetic number, because the mean of its divisors is an integer number (66722215067026).

Almost surely, 2^{133444430134051} is an apocalyptic number.

133444430134051 is a deficient number, since it is larger than the sum of its proper divisors (1).

133444430134051 is an equidigital number, since it uses as much as digits as its factorization.

133444430134051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 414720, while the sum is 40.

Adding to 133444430134051 its reverse (150431034444331), we get a palindrome (283875464578382).

The spelling of 133444430134051 in words is "one hundred thirty-three trillion, four hundred forty-four billion, four hundred thirty million, one hundred thirty-four thousand, fifty-one".