Base | Representation |
---|---|
bin | 11110010110000110010101… |
… | …010010011111001011010011 |
3 | 122111112122122111112121201012 |
4 | 132112012111102133023103 |
5 | 114443102112000040313 |
6 | 1151502404404201135 |
7 | 40053111536531654 |
oct | 3626062522371323 |
9 | 574478574477635 |
10 | 133460023440083 |
11 | 39585094a3322a |
12 | 12b755439991ab |
13 | 59612c2c99772 |
14 | 24d56dcc8d52b |
15 | 1066905018da8 |
hex | 79619549f2d3 |
133460023440083 has 2 divisors, whose sum is σ = 133460023440084. Its totient is φ = 133460023440082.
The previous prime is 133460023439947. The next prime is 133460023440109. The reversal of 133460023440083 is 380044320064331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133460023440083 - 228 = 133459755004627 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133460023440083.
It is not a weakly prime, because it can be changed into another prime (133460020440083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66730011720041 + 66730011720042.
It is an arithmetic number, because the mean of its divisors is an integer number (66730011720042).
Almost surely, 2133460023440083 is an apocalyptic number.
133460023440083 is a deficient number, since it is larger than the sum of its proper divisors (1).
133460023440083 is an equidigital number, since it uses as much as digits as its factorization.
133460023440083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 497664, while the sum is 41.
The spelling of 133460023440083 in words is "one hundred thirty-three trillion, four hundred sixty billion, twenty-three million, four hundred forty thousand, eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •