Base | Representation |
---|---|
bin | 111110001001011100… |
… | …1000011000111100001 |
3 | 110202111010021202110222 |
4 | 1330102321003013201 |
5 | 4141311444243131 |
6 | 141151110532425 |
7 | 12433200124214 |
oct | 1742271030741 |
9 | 422433252428 |
10 | 133460931041 |
11 | 51667241919 |
12 | 21a47967115 |
13 | c77bc12319 |
14 | 6660db777b |
15 | 3711b0487b |
hex | 1f12e431e1 |
133460931041 has 2 divisors, whose sum is σ = 133460931042. Its totient is φ = 133460931040.
The previous prime is 133460931031. The next prime is 133460931073. The reversal of 133460931041 is 140139064331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 92698936225 + 40761994816 = 304465^2 + 201896^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133460931041 is a prime.
It is a super-2 number, since 2×1334609310412 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 133460930992 and 133460931010.
It is not a weakly prime, because it can be changed into another prime (133460931011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66730465520 + 66730465521.
It is an arithmetic number, because the mean of its divisors is an integer number (66730465521).
Almost surely, 2133460931041 is an apocalyptic number.
It is an amenable number.
133460931041 is a deficient number, since it is larger than the sum of its proper divisors (1).
133460931041 is an equidigital number, since it uses as much as digits as its factorization.
133460931041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23328, while the sum is 35.
Adding to 133460931041 its reverse (140139064331), we get a palindrome (273599995372).
The spelling of 133460931041 in words is "one hundred thirty-three billion, four hundred sixty million, nine hundred thirty-one thousand, forty-one".
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