Base | Representation |
---|---|
bin | 10011011011000000011… |
… | …010111011100001101001 |
3 | 11201121000022120210010221 |
4 | 103123000122323201221 |
5 | 133331400021144133 |
6 | 2501045454210041 |
7 | 165266215030552 |
oct | 23330032734151 |
9 | 4647008523127 |
10 | 1334668146793 |
11 | 475036412a83 |
12 | 1968017b3921 |
13 | 98b21649977 |
14 | 4885398d329 |
15 | 24ab77a3a2d |
hex | 136c06bb869 |
1334668146793 has 2 divisors, whose sum is σ = 1334668146794. Its totient is φ = 1334668146792.
The previous prime is 1334668146787. The next prime is 1334668146821. The reversal of 1334668146793 is 3976418664331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1201102018704 + 133566128089 = 1095948^2 + 365467^2 .
It is an emirp because it is prime and its reverse (3976418664331) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1334668146793 is a prime.
It is not a weakly prime, because it can be changed into another prime (1334668146193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667334073396 + 667334073397.
It is an arithmetic number, because the mean of its divisors is an integer number (667334073397).
Almost surely, 21334668146793 is an apocalyptic number.
It is an amenable number.
1334668146793 is a deficient number, since it is larger than the sum of its proper divisors (1).
1334668146793 is an equidigital number, since it uses as much as digits as its factorization.
1334668146793 is an evil number, because the sum of its binary digits is even.
The product of its digits is 47029248, while the sum is 61.
The spelling of 1334668146793 in words is "one trillion, three hundred thirty-four billion, six hundred sixty-eight million, one hundred forty-six thousand, seven hundred ninety-three".
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