Base | Representation |
---|---|
bin | 1100001000111001110110… |
… | …0101000000010111110010 |
3 | 1202020222012211202210221112 |
4 | 3002032131211000113302 |
5 | 3222134333410044214 |
6 | 44215324254353322 |
7 | 2545203520361204 |
oct | 302163545002762 |
9 | 52228184683845 |
10 | 13347107112434 |
11 | 4286527008877 |
12 | 15b69131bb842 |
13 | 75a81c106444 |
14 | 3420095b4774 |
15 | 1822c7753a3e |
hex | c239d9405f2 |
13347107112434 has 8 divisors (see below), whose sum is σ = 20020676268528. Its totient is φ = 6673548356260.
The previous prime is 13347107112421. The next prime is 13347107112503. The reversal of 13347107112434 is 43421170174331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13347107112391 and 13347107112400.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3165389 + ... + 6059199.
It is an arithmetic number, because the mean of its divisors is an integer number (2502584533566).
Almost surely, 213347107112434 is an apocalyptic number.
13347107112434 is a deficient number, since it is larger than the sum of its proper divisors (6673569156094).
13347107112434 is a wasteful number, since it uses less digits than its factorization.
13347107112434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5199960.
The product of its (nonzero) digits is 169344, while the sum is 41.
Adding to 13347107112434 its reverse (43421170174331), we get a palindrome (56768277286765).
The spelling of 13347107112434 in words is "thirteen trillion, three hundred forty-seven billion, one hundred seven million, one hundred twelve thousand, four hundred thirty-four".
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