Base | Representation |
---|---|
bin | 11000110111001010… |
… | …11111011101111001 |
3 | 1021110020002011200111 |
4 | 30123211133131321 |
5 | 204314003334222 |
6 | 10044251504321 |
7 | 651524463544 |
oct | 143345373571 |
9 | 37406064614 |
10 | 13347714937 |
11 | 572a489877 |
12 | 27061580a1 |
13 | 1349437a9b |
14 | 9089dd85b |
15 | 531c38777 |
hex | 31b95f779 |
13347714937 has 2 divisors, whose sum is σ = 13347714938. Its totient is φ = 13347714936.
The previous prime is 13347714827. The next prime is 13347714949. The reversal of 13347714937 is 73941774331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10687631161 + 2660083776 = 103381^2 + 51576^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13347714937 is a prime.
It is a super-2 number, since 2×133477149372 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13347714337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6673857468 + 6673857469.
It is an arithmetic number, because the mean of its divisors is an integer number (6673857469).
Almost surely, 213347714937 is an apocalyptic number.
It is an amenable number.
13347714937 is a deficient number, since it is larger than the sum of its proper divisors (1).
13347714937 is an equidigital number, since it uses as much as digits as its factorization.
13347714937 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1333584, while the sum is 49.
The spelling of 13347714937 in words is "thirteen billion, three hundred forty-seven million, seven hundred fourteen thousand, nine hundred thirty-seven".
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