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133509094993 = 411132476063
BaseRepresentation
bin111110001010111000…
…0110001111001010001
3110202121110220202000001
41330111300301321101
54141411312014433
6141155551130001
712434323404001
oct1742560617121
9422543822001
10133509094993
115169144913a
1221a5bb13901
13c788ba6ac1
146667554001
153715e6a57d
hex1f15c31e51

133509094993 has 4 divisors (see below), whose sum is σ = 133541575168. Its totient is φ = 133476614820.

The previous prime is 133509094973. The next prime is 133509094997. The reversal of 133509094993 is 399490905331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133509094993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133509094997) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16233921 + ... + 16242142.

It is an arithmetic number, because the mean of its divisors is an integer number (33385393792).

Almost surely, 2133509094993 is an apocalyptic number.

It is an amenable number.

133509094993 is a deficient number, since it is larger than the sum of its proper divisors (32480175).

133509094993 is an equidigital number, since it uses as much as digits as its factorization.

133509094993 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32480174.

The product of its (nonzero) digits is 3542940, while the sum is 55.

The spelling of 133509094993 in words is "one hundred thirty-three billion, five hundred nine million, ninety-four thousand, nine hundred ninety-three".

Divisors: 1 4111 32476063 133509094993