Base | Representation |
---|---|
bin | 11110010110110110000010… |
… | …001011000000100110110011 |
3 | 122111201112212000220022200001 |
4 | 132112312002023000212303 |
5 | 114444422011013222212 |
6 | 1151542115030410431 |
7 | 40056604022036245 |
oct | 3626660213004663 |
9 | 574645760808601 |
10 | 133511242320307 |
11 | 395a4888728005 |
12 | 12b83458b00a17 |
13 | 5966096411497 |
14 | 24d7d9b426095 |
15 | 1067e018c8657 |
hex | 796d822c09b3 |
133511242320307 has 4 divisors (see below), whose sum is σ = 137818056588736. Its totient is φ = 129204428051880.
The previous prime is 133511242320301. The next prime is 133511242320367. The reversal of 133511242320307 is 703023242115331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133511242320307 - 23 = 133511242320299 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133511242320301) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2153407134168 + ... + 2153407134229.
It is an arithmetic number, because the mean of its divisors is an integer number (34454514147184).
Almost surely, 2133511242320307 is an apocalyptic number.
133511242320307 is a deficient number, since it is larger than the sum of its proper divisors (4306814268429).
133511242320307 is an equidigital number, since it uses as much as digits as its factorization.
133511242320307 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4306814268428.
The product of its (nonzero) digits is 90720, while the sum is 37.
Adding to 133511242320307 its reverse (703023242115331), we get a palindrome (836534484435638).
The spelling of 133511242320307 in words is "one hundred thirty-three trillion, five hundred eleven billion, two hundred forty-two million, three hundred twenty thousand, three hundred seven".
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