Base | Representation |
---|---|
bin | 11000110111100101… |
… | …00100110000000011 |
3 | 1021110110112102002112 |
4 | 30123302210300003 |
5 | 204320343110301 |
6 | 10044453205535 |
7 | 651565566251 |
oct | 143362446003 |
9 | 37413472075 |
10 | 13351144451 |
11 | 5731411487 |
12 | 27073308ab |
13 | 134a068a98 |
14 | 9092535d1 |
15 | 5321b49bb |
hex | 31bca4c03 |
13351144451 has 4 divisors (see below), whose sum is σ = 13501157400. Its totient is φ = 13201131504.
The previous prime is 13351144427. The next prime is 13351144453. The reversal of 13351144451 is 15444115331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13351144451 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13351144453) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 75006341 + ... + 75006518.
It is an arithmetic number, because the mean of its divisors is an integer number (3375289350).
Almost surely, 213351144451 is an apocalyptic number.
13351144451 is a deficient number, since it is larger than the sum of its proper divisors (150012949).
13351144451 is an equidigital number, since it uses as much as digits as its factorization.
13351144451 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 150012948.
The product of its digits is 14400, while the sum is 32.
Adding to 13351144451 its reverse (15444115331), we get a palindrome (28795259782).
The spelling of 13351144451 in words is "thirteen billion, three hundred fifty-one million, one hundred forty-four thousand, four hundred fifty-one".
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