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1335120344531 is a prime number
BaseRepresentation
bin10011011011011011010…
…111111011010111010011
311201122011211110210211022
4103123123113323113103
5133333311302011111
62501202410310055
7165313345452401
oct23333327732723
94648154423738
101335120344531
1147524869a916
1219690912832b
1398b94235aac
1448897a60471
1524ae23282db
hex136db5fb5d3

1335120344531 has 2 divisors, whose sum is σ = 1335120344532. Its totient is φ = 1335120344530.

The previous prime is 1335120344521. The next prime is 1335120344557. The reversal of 1335120344531 is 1354430215331.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1335120344531 - 226 = 1335053235667 is a prime.

It is a super-2 number, since 2×13351203445312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1335120344491 and 1335120344500.

It is not a weakly prime, because it can be changed into another prime (1335120344521) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667560172265 + 667560172266.

It is an arithmetic number, because the mean of its divisors is an integer number (667560172266).

Almost surely, 21335120344531 is an apocalyptic number.

1335120344531 is a deficient number, since it is larger than the sum of its proper divisors (1).

1335120344531 is an equidigital number, since it uses as much as digits as its factorization.

1335120344531 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64800, while the sum is 35.

Adding to 1335120344531 its reverse (1354430215331), we get a palindrome (2689550559862).

The spelling of 1335120344531 in words is "one trillion, three hundred thirty-five billion, one hundred twenty million, three hundred forty-four thousand, five hundred thirty-one".