Base | Representation |
---|---|
bin | 10011011011011011010… |
… | …111111011010111010011 |
3 | 11201122011211110210211022 |
4 | 103123123113323113103 |
5 | 133333311302011111 |
6 | 2501202410310055 |
7 | 165313345452401 |
oct | 23333327732723 |
9 | 4648154423738 |
10 | 1335120344531 |
11 | 47524869a916 |
12 | 19690912832b |
13 | 98b94235aac |
14 | 48897a60471 |
15 | 24ae23282db |
hex | 136db5fb5d3 |
1335120344531 has 2 divisors, whose sum is σ = 1335120344532. Its totient is φ = 1335120344530.
The previous prime is 1335120344521. The next prime is 1335120344557. The reversal of 1335120344531 is 1354430215331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1335120344531 - 226 = 1335053235667 is a prime.
It is a super-2 number, since 2×13351203445312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1335120344491 and 1335120344500.
It is not a weakly prime, because it can be changed into another prime (1335120344521) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 667560172265 + 667560172266.
It is an arithmetic number, because the mean of its divisors is an integer number (667560172266).
Almost surely, 21335120344531 is an apocalyptic number.
1335120344531 is a deficient number, since it is larger than the sum of its proper divisors (1).
1335120344531 is an equidigital number, since it uses as much as digits as its factorization.
1335120344531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 1335120344531 its reverse (1354430215331), we get a palindrome (2689550559862).
The spelling of 1335120344531 in words is "one trillion, three hundred thirty-five billion, one hundred twenty million, three hundred forty-four thousand, five hundred thirty-one".
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