1335141125642 has 4 divisors (see below), whose sum is σ = 2002711688466. Its totient is φ = 667570562820.

The previous prime is 1335141125627. The next prime is 1335141125651. The reversal of 1335141125642 is 2465211415331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1226886307201 + 108254818441 = 1107649^2 + 329021^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1335141125596 and 1335141125605.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 333785281409 + ... + 333785281412.

Almost surely, 2^{1335141125642} is an apocalyptic number.

1335141125642 is a deficient number, since it is larger than the sum of its proper divisors (667570562824).

1335141125642 is an equidigital number, since it uses as much as digits as its factorization.

1335141125642 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 667570562823.

The product of its digits is 86400, while the sum is 38.

The spelling of 1335141125642 in words is "one trillion, three hundred thirty-five billion, one hundred forty-one million, one hundred twenty-five thousand, six hundred forty-two".