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13351530405443 = 55939723867719
BaseRepresentation
bin1100001001001010010100…
…1110100001111001000011
31202021101122002222101020112
43002102211032201321003
53222222413240433233
644221335225101535
72545421240632166
oct302224516417103
952241562871215
1013351530405443
11428839692732a
1215b77486278ab
1375b075633699
14342308c33add
15182485c3e048
hexc24a53a1e43

13351530405443 has 4 divisors (see below), whose sum is σ = 13351554832560. Its totient is φ = 13351505978328.

The previous prime is 13351530405439. The next prime is 13351530405467. The reversal of 13351530405443 is 34450403515331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13351530405443 - 22 = 13351530405439 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13351530405443.

It is not an unprimeable number, because it can be changed into a prime (13351530405943) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11374463 + ... + 12493256.

It is an arithmetic number, because the mean of its divisors is an integer number (3337888708140).

Almost surely, 213351530405443 is an apocalyptic number.

13351530405443 is a deficient number, since it is larger than the sum of its proper divisors (24427117).

13351530405443 is an equidigital number, since it uses as much as digits as its factorization.

13351530405443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24427116.

The product of its (nonzero) digits is 648000, while the sum is 41.

The spelling of 13351530405443 in words is "thirteen trillion, three hundred fifty-one billion, five hundred thirty million, four hundred five thousand, four hundred forty-three".

Divisors: 1 559397 23867719 13351530405443