Base | Representation |
---|---|
bin | 1100001001001010010101… |
… | …0101100000000110100001 |
3 | 1202021101122020102020100022 |
4 | 3002102211111200012201 |
5 | 3222222414222424441 |
6 | 44221335332203225 |
7 | 2545421262313535 |
oct | 302224525400641 |
9 | 52241566366308 |
10 | 13351532233121 |
11 | 4288397965505 |
12 | 15b7749169515 |
13 | 75b075b23554 |
14 | 34230918bbc5 |
15 | 182485ea084b |
hex | c24a55601a1 |
13351532233121 has 2 divisors, whose sum is σ = 13351532233122. Its totient is φ = 13351532233120.
The previous prime is 13351532233027. The next prime is 13351532233133. The reversal of 13351532233121 is 12133223515331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8053875064225 + 5297657168896 = 2837935^2 + 2301664^2 .
It is a cyclic number.
It is not a de Polignac number, because 13351532233121 - 210 = 13351532232097 is a prime.
It is a super-4 number, since 4×133515322331214 (a number of 54 digits) contains 4444 as substring.
It is not a weakly prime, because it can be changed into another prime (13351532230121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6675766116560 + 6675766116561.
It is an arithmetic number, because the mean of its divisors is an integer number (6675766116561).
Almost surely, 213351532233121 is an apocalyptic number.
It is an amenable number.
13351532233121 is a deficient number, since it is larger than the sum of its proper divisors (1).
13351532233121 is an equidigital number, since it uses as much as digits as its factorization.
13351532233121 is an evil number, because the sum of its binary digits is even.
The product of its digits is 48600, while the sum is 35.
Adding to 13351532233121 its reverse (12133223515331), we get a palindrome (25484755748452).
The spelling of 13351532233121 in words is "thirteen trillion, three hundred fifty-one billion, five hundred thirty-two million, two hundred thirty-three thousand, one hundred twenty-one".
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