Base | Representation |
---|---|
bin | 100111110010101… |
… | …1000100100110011 |
3 | 10110001102012010202 |
4 | 1033211120210303 |
5 | 10213302400201 |
6 | 340253545415 |
7 | 45042004343 |
oct | 11745304463 |
9 | 3401365122 |
10 | 1335200051 |
11 | 62575a619 |
12 | 3131a526b |
13 | 183810b03 |
14 | c9484d23 |
15 | 7c344c6b |
hex | 4f958933 |
1335200051 has 4 divisors (see below), whose sum is σ = 1336723392. Its totient is φ = 1333676712.
The previous prime is 1335200033. The next prime is 1335200057. The reversal of 1335200051 is 1500025331.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1500025331 = 7 ⋅214289333.
It is a cyclic number.
It is not a de Polignac number, because 1335200051 - 222 = 1331005747 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1335199996 and 1335200032.
It is not an unprimeable number, because it can be changed into a prime (1335200057) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 760355 + ... + 762108.
It is an arithmetic number, because the mean of its divisors is an integer number (334180848).
Almost surely, 21335200051 is an apocalyptic number.
1335200051 is a deficient number, since it is larger than the sum of its proper divisors (1523341).
1335200051 is an equidigital number, since it uses as much as digits as its factorization.
1335200051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1523340.
The product of its (nonzero) digits is 450, while the sum is 20.
The square root of 1335200051 is about 36540.3893110076. The cubic root of 1335200051 is about 1101.1558239367.
Adding to 1335200051 its reverse (1500025331), we get a palindrome (2835225382).
The spelling of 1335200051 in words is "one billion, three hundred thirty-five million, two hundred thousand, fifty-one".
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