Base | Representation |
---|---|
bin | 1100001001001100000111… |
… | …0100111101111111010011 |
3 | 1202021102212112212201001211 |
4 | 3002103001310331333103 |
5 | 3222224404110302201 |
6 | 44221455005440551 |
7 | 2545436155325443 |
oct | 302230164757723 |
9 | 52242775781054 |
10 | 13352010244051 |
11 | 4288612773166 |
12 | 15b7861270157 |
13 | 75b120b79a5b |
14 | 34235285c123 |
15 | 1824b2e23651 |
hex | c24c1d3dfd3 |
13352010244051 has 16 divisors (see below), whose sum is σ = 13576814102016. Its totient is φ = 13129506000000.
The previous prime is 13352010244031. The next prime is 13352010244189. The reversal of 13352010244051 is 15044201025331.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13352010244051 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13352010244031) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7090546 + ... + 8773816.
It is an arithmetic number, because the mean of its divisors is an integer number (848550881376).
Almost surely, 213352010244051 is an apocalyptic number.
13352010244051 is a deficient number, since it is larger than the sum of its proper divisors (224803857965).
13352010244051 is a wasteful number, since it uses less digits than its factorization.
13352010244051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1683954.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 13352010244051 its reverse (15044201025331), we get a palindrome (28396211269382).
The spelling of 13352010244051 in words is "thirteen trillion, three hundred fifty-two billion, ten million, two hundred forty-four thousand, fifty-one".
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