Base | Representation |
---|---|
bin | 11110010111000001001100… |
… | …010011011010000110010001 |
3 | 122111202200210000111222102222 |
4 | 132113001030103122012101 |
5 | 120000121030201012342 |
6 | 1151551415543550425 |
7 | 40060506644015411 |
oct | 3627011423320621 |
9 | 574680700458388 |
10 | 133523223454097 |
11 | 395a9976773174 |
12 | 12b8584145b415 |
13 | 596725569b969 |
14 | 24d87b6732641 |
15 | 10683a366ded2 |
hex | 79704c4da191 |
133523223454097 has 2 divisors, whose sum is σ = 133523223454098. Its totient is φ = 133523223454096.
The previous prime is 133523223454091. The next prime is 133523223454111. The reversal of 133523223454097 is 790454322325331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 98994719252881 + 34528504201216 = 9949609^2 + 5876096^2 .
It is a cyclic number.
It is not a de Polignac number, because 133523223454097 - 214 = 133523223437713 is a prime.
It is not a weakly prime, because it can be changed into another prime (133523223454091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66761611727048 + 66761611727049.
It is an arithmetic number, because the mean of its divisors is an integer number (66761611727049).
Almost surely, 2133523223454097 is an apocalyptic number.
It is an amenable number.
133523223454097 is a deficient number, since it is larger than the sum of its proper divisors (1).
133523223454097 is an equidigital number, since it uses as much as digits as its factorization.
133523223454097 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16329600, while the sum is 53.
The spelling of 133523223454097 in words is "one hundred thirty-three trillion, five hundred twenty-three billion, two hundred twenty-three million, four hundred fifty-four thousand, ninety-seven".
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