Base | Representation |
---|---|
bin | 11110010111000001010111… |
… | …101110111011001000001010 |
3 | 122111202201021101100112012202 |
4 | 132113001113232323020022 |
5 | 120000121423243413100 |
6 | 1151551450554040202 |
7 | 40060514462664044 |
oct | 3627012756731012 |
9 | 574681241315182 |
10 | 133523415216650 |
11 | 395a9a64a3a218 |
12 | 12b85895719062 |
13 | 5967286330724 |
14 | 24d87d3daca94 |
15 | 10683b53ec7d5 |
hex | 797057bbb20a |
133523415216650 has 12 divisors (see below), whose sum is σ = 248353552303062. Its totient is φ = 53409366086640.
The previous prime is 133523415216647. The next prime is 133523415216671. The reversal of 133523415216650 is 56612514325331.
It can be written as a sum of positive squares in 3 ways, for example, as 128500747057489 + 5022668159161 = 11335817^2 + 2241131^2 .
It is a super-2 number, since 2×1335234152166502 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 133523415216595 and 133523415216604.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1335234152117 + ... + 1335234152216.
Almost surely, 2133523415216650 is an apocalyptic number.
133523415216650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133523415216650 is a deficient number, since it is larger than the sum of its proper divisors (114830137086412).
133523415216650 is a wasteful number, since it uses less digits than its factorization.
133523415216650 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2670468304345 (or 2670468304340 counting only the distinct ones).
The product of its (nonzero) digits is 1944000, while the sum is 47.
The spelling of 133523415216650 in words is "one hundred thirty-three trillion, five hundred twenty-three billion, four hundred fifteen million, two hundred sixteen thousand, six hundred fifty".
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