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133524152133313 is a prime number
BaseRepresentation
bin11110010111000010000011…
…101010000010011011000001
3122111202210011201222202211111
4132113002003222002123001
5120000124430421231223
61151552052040443321
740060541651452114
oct3627020352023301
9574683151882744
10133524152133313
11395aa302a03657
1212b85a60479541
135967372bc70a6
1424d8863bd657b
151068409e6330d
hex797083a826c1

133524152133313 has 2 divisors, whose sum is σ = 133524152133314. Its totient is φ = 133524152133312.

The previous prime is 133524152133299. The next prime is 133524152133367. The reversal of 133524152133313 is 313331251425331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 112131834349824 + 21392317783489 = 10589232^2 + 4625183^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133524152133313 is a prime.

It is a super-2 number, since 2×1335241521333132 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (133524152133013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66762076066656 + 66762076066657.

It is an arithmetic number, because the mean of its divisors is an integer number (66762076066657).

Almost surely, 2133524152133313 is an apocalyptic number.

It is an amenable number.

133524152133313 is a deficient number, since it is larger than the sum of its proper divisors (1).

133524152133313 is an equidigital number, since it uses as much as digits as its factorization.

133524152133313 is an evil number, because the sum of its binary digits is even.

The product of its digits is 291600, while the sum is 40.

The spelling of 133524152133313 in words is "one hundred thirty-three trillion, five hundred twenty-four billion, one hundred fifty-two million, one hundred thirty-three thousand, three hundred thirteen".