Base | Representation |
---|---|
bin | 1100001001001101101111… |
… | …0000011000101000110001 |
3 | 1202021110222212102022011212 |
4 | 3002103123300120220301 |
5 | 3222231301441000342 |
6 | 44222010105245505 |
7 | 2545453016655602 |
oct | 302233360305061 |
9 | 52243885368155 |
10 | 13352445250097 |
11 | 4288816278698 |
12 | 15b7962a93895 |
13 | 75b190026a95 |
14 | 342394535da9 |
15 | 1824db1ee182 |
hex | c24dbc18a31 |
13352445250097 has 2 divisors, whose sum is σ = 13352445250098. Its totient is φ = 13352445250096.
The previous prime is 13352445250049. The next prime is 13352445250117. The reversal of 13352445250097 is 79005254425331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9590393210896 + 3762052039201 = 3096836^2 + 1939601^2 .
It is a cyclic number.
It is not a de Polignac number, because 13352445250097 - 26 = 13352445250033 is a prime.
It is not a weakly prime, because it can be changed into another prime (13352445250597) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676222625048 + 6676222625049.
It is an arithmetic number, because the mean of its divisors is an integer number (6676222625049).
Almost surely, 213352445250097 is an apocalyptic number.
It is an amenable number.
13352445250097 is a deficient number, since it is larger than the sum of its proper divisors (1).
13352445250097 is an equidigital number, since it uses as much as digits as its factorization.
13352445250097 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4536000, while the sum is 50.
The spelling of 13352445250097 in words is "thirteen trillion, three hundred fifty-two billion, four hundred forty-five million, two hundred fifty thousand, ninety-seven".
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