13352500205403 has 4 divisors (see below), whose sum is σ = 17803333607208. Its totient is φ = 8901666803600.

The previous prime is 13352500205389. The next prime is 13352500205419. The reversal of 13352500205403 is 30450200525331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13352500205403 - 2³⁸ = 13077622298459 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13352500205453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2225416700898 + ... + 2225416700903.

It is an arithmetic number, because the mean of its divisors is an integer number (4450833401802).

Almost surely, 2^{13352500205403} is an apocalyptic number.

13352500205403 is a deficient number, since it is larger than the sum of its proper divisors (4450833401805).

13352500205403 is an equidigital number, since it uses as much as digits as its factorization.

13352500205403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4450833401804.

The product of its (nonzero) digits is 54000, while the sum is 33.

The spelling of 13352500205403 in words is "thirteen trillion, three hundred fifty-two billion, five hundred million, two hundred five thousand, four hundred three".