Base | Representation |
---|---|
bin | 1100001001001110000001… |
… | …1110100001000100010001 |
3 | 1202021111012101110011220212 |
4 | 3002103200132201010101 |
5 | 3222231432224431423 |
6 | 44222022015013505 |
7 | 2545455001116350 |
oct | 302234036410421 |
9 | 52244171404825 |
10 | 13352524452113 |
11 | 4288856a54300 |
12 | 15b798550a295 |
13 | 75b1a3567b92 |
14 | 3423a0c71997 |
15 | 1824e3146578 |
hex | c24e07a1111 |
13352524452113 has 48 divisors (see below), whose sum is σ = 16865756506368. Its totient is φ = 10347422131200.
The previous prime is 13352524452107. The next prime is 13352524452119. The reversal of 13352524452113 is 31125442525331.
It is an interprime number because it is at equal distance from previous prime (13352524452107) and next prime (13352524452119).
It is not a de Polignac number, because 13352524452113 - 26 = 13352524452049 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13352524452119) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 132046733 + ... + 132147813.
It is an arithmetic number, because the mean of its divisors is an integer number (351369927216).
Almost surely, 213352524452113 is an apocalyptic number.
It is an amenable number.
13352524452113 is a deficient number, since it is larger than the sum of its proper divisors (3513232054255).
13352524452113 is a wasteful number, since it uses less digits than its factorization.
13352524452113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 101966 (or 101955 counting only the distinct ones).
The product of its digits is 432000, while the sum is 41.
Adding to 13352524452113 its reverse (31125442525331), we get a palindrome (44477966977444).
The spelling of 13352524452113 in words is "thirteen trillion, three hundred fifty-two billion, five hundred twenty-four million, four hundred fifty-two thousand, one hundred thirteen".
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