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13352540030171 is a prime number
BaseRepresentation
bin1100001001001110000101…
…1001111100010011011011
31202021111020110202121222222
43002103201121330103123
53222232000221431141
644222023332534255
72545455250410416
oct302234131742333
952244213677888
1013352540030171
114288864824331
1215b798a78138b
1375b1a6860674
143423a2d68b7d
151824e46c214b
hexc24e167c4db

13352540030171 has 2 divisors, whose sum is σ = 13352540030172. Its totient is φ = 13352540030170.

The previous prime is 13352540030083. The next prime is 13352540030183. The reversal of 13352540030171 is 17103004525331.

13352540030171 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13352540030171 is a prime.

It is not a weakly prime, because it can be changed into another prime (13352540030671) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676270015085 + 6676270015086.

It is an arithmetic number, because the mean of its divisors is an integer number (6676270015086).

Almost surely, 213352540030171 is an apocalyptic number.

13352540030171 is a deficient number, since it is larger than the sum of its proper divisors (1).

13352540030171 is an equidigital number, since it uses as much as digits as its factorization.

13352540030171 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 37800, while the sum is 35.

The spelling of 13352540030171 in words is "thirteen trillion, three hundred fifty-two billion, five hundred forty million, thirty thousand, one hundred seventy-one".