Base | Representation |
---|---|
bin | 11000110111110011… |
… | …10001000110100011 |
3 | 1021110121002012122120 |
4 | 30123321301012203 |
5 | 204321333430201 |
6 | 10045001435323 |
7 | 651620611524 |
oct | 143371610643 |
9 | 37417065576 |
10 | 13353030051 |
11 | 573248a129 |
12 | 2707a9bb43 |
13 | 134a57911a |
14 | 9095c484b |
15 | 532438536 |
hex | 31be711a3 |
13353030051 has 4 divisors (see below), whose sum is σ = 17804040072. Its totient is φ = 8902020032.
The previous prime is 13353030049. The next prime is 13353030109. The reversal of 13353030051 is 15003035331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13353030051 - 21 = 13353030049 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13353030151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2225505006 + ... + 2225505011.
It is an arithmetic number, because the mean of its divisors is an integer number (4451010018).
Almost surely, 213353030051 is an apocalyptic number.
13353030051 is a deficient number, since it is larger than the sum of its proper divisors (4451010021).
13353030051 is an equidigital number, since it uses as much as digits as its factorization.
13353030051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4451010020.
The product of its (nonzero) digits is 2025, while the sum is 24.
Adding to 13353030051 its reverse (15003035331), we get a palindrome (28356065382).
The spelling of 13353030051 in words is "thirteen billion, three hundred fifty-three million, thirty thousand, fifty-one".
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